EJCN

This function evaluates the Jacobi elliptic function cn(x, m).

Function Return Value

EJCN — Real or complex function value. (Output)

Required Arguments

X — Real or complex argument for which the function value is desired. (Input)

AM — Parameter of the elliptic function (m = k2). (Input)

FORTRAN 90 Interface

Generic: EJCN (X, AM)

Specific: The specific interface names are S_EJCN, D_EJCN, C_EJCN, and Z_EJCN.

FORTRAN 77 Interface

Single: EJCN (X, AM)

Double: The double precision name is DEJCN.

Complex: The complex name is CEJCN.

Double Complex:    The double complex name is ZEJCN.

Description

The Jacobi elliptic function cn(x, m) = cos ɸ, where the amplitude ɸ is defined by the following:

 

The function cn(x, m) is computed by first applying, if necessary, a Jacobi transformation so that the parameter, m, is between zero and one. Then, a descending Landen (Gauss) transform is applied until the parameter is small. The small parameter approximation is then applied.

Comments

Informational errors

 

Type

Code

Description

3

2

The result is accurate to less than one half precision because X is too large.

3

2

The result is accurate to less than one half precision because REAL (Z) is too large.

3

3

The result is accurate to less than one half precision because AIMAG (Z) is too large.

3

5

Landen transform did not converge. Result may not be accurate. This should never occur.

Examples

Example 1

In this example, cn(1.5, 0.5) is computed and printed.

 

USE EJCN_INT

USE UMACH_INT

 

IMPLICIT NONE

! Declare variables

INTEGER NOUT

REAL AM, VALUE, X

! Compute

AM = 0.5

X = 1.5

VALUE = EJCN(X, AM)

! Print the results

CALL UMACH (2, NOUT)

WRITE (NOUT,99999) X, AM, VALUE

99999 FORMAT (' EJCN(', F6.3, ',', F6.3, ') = ', F6.3)

END

Output

 

EJCN( 1.500, 0.500) = 0.250

Example 2

In this example, cn(1.5 + 0.3i, 0.5) is computed and printed.

 

USE EJCN_INT

USE UMACH_INT

 

IMPLICIT NONE

! Declare variables

INTEGER NOUT

REAL AM

COMPLEX VALUE, Z

! Compute

Z = (1.5, 0.3)

AM = 0.5

VALUE = EJCN(Z, AM)

! Print the results

CALL UMACH (2, NOUT)

WRITE (NOUT,99999) Z, AM, VALUE

99999 FORMAT (' EJCN((', F6.3, ',', F6.3, '), ', F6.3, ') = (', &

F6.3, ',', F6.3, ')')

END

Output

 

EJCN(( 1.500, 0.300), 0.500) = ( 0.251,-0.212)