Example 2: Nonlinear least-squares problem
A nonlinear least-squares problem is solved using a user-supplied Jacobian.
import com.imsl.math.*;
public class NonlinLeastSquaresEx2 {
public static void main(String args[]) throws
NonlinLeastSquares.TooManyIterationsException,
NonlinLeastSquares.NoProgressException {
NonlinLeastSquares.Jacobian zsj = new NonlinLeastSquares.Jacobian() {
public void f(double x[], double f[]) {
f[0] = 10. * (x[1] - x[0]*x[0]);
f[1] = 1. - x[0];
}
public void jacobian(double x[], double fjac[][]) {
fjac[0][0] = -20.*x[0];
fjac[1][0] = 10.;
fjac[0][1] = -1.;
fjac[1][1] = 0.;
}
};
int m = 2;
int n = 2;
double xguess[] = {-1.2, 1.};
double xscale[] = {1., 1.};
double fscale[] = {1., 1.};
double x[] = new double[2];
NonlinLeastSquares zs = new NonlinLeastSquares(m,n);
zs.setGuess(xguess);
zs.setXscale(xscale);
zs.setFscale(fscale);
x = zs.solve(zsj);
for (int k = 0; k < n; k++) {
System.out.println("x["+k+"] = "+x[k]);
}
}
}
Output
x[0] = 1.0
x[1] = 1.0
Link to Java source.