Minimum of a smooth function

Example 2: Minimum of a smooth function

The minimum of

is found using function evaluations and first derivative evaluations.

using System;
using Imsl.Math;

public class MinUnconEx2 : MinUncon.IDerivative
{
	public double F(double x)
	{
		return Math.Exp(x) - 5.0 * x;
	}
	
	public double Derivative(double x)
	{
		return Math.Exp(x) - 5.0;
	}
	

	public static void  Main(String[] args)
	{
		MinUncon zf = new MinUncon();
		zf.Guess = 0.0;
		zf.Accuracy = .001;
		double x = zf.ComputeMin(new MinUnconEx2());
		Console.Out.WriteLine("x = " + x);
	}
}

Output

x = 1.61001131622703

Link to C# source.