gammaCdf¶
Evaluates the gamma distribution function.
Synopsis¶
gammaCdf (x, a)
Required Arguments¶
- float
x
(Input) - Argument for which the gamma distribution function is to be evaluated.
- float
a
(Input) - Shape parameter of the gamma distribution. This parameter must be positive.
Return Value¶
The probability that a gamma random variable takes a value less than or
equal to x
.
Description¶
Function gammaCdf
evaluates the distribution function, F, of a gamma
random variable with shape parameter a,
where Γ(⋅) is the gamma function. (The gamma function is the integral from 0 to ∞ of the same integrand as above.) The value of the distribution function at the point x is the probability that the random variable takes a value less than or equal to x.
The gamma distribution is often defined as a two-parameter distribution with a scale parameter b (which must be positive) or as a three-parameter distribution in which the third parameter c is a location parameter. In the most general case, the probability density function over (c, ∞) is as follows:
If T is a random variable with parameters a, b, and c, the
probability that \(T\leq t_0\) can be obtained from gammaCdf
by
setting \(x=(t_0-c)/b\).
If x is less than a or less than or equal to 1.0, gammaCdf
uses a
series expansion; otherwise, a continued fraction expansion is used. (See
Abramowitz and Stegun 1964.)
Example¶
Let X be a gamma random variable with a shape parameter of four. (In this case, it has an Erlang distribution since the shape parameter is an integer.) This example finds the probability that X is less than 0.5 and the probability that X is between 0.5 and 1.0.
from __future__ import print_function
from numpy import *
from pyimsl.stat.gammaCdf import gammaCdf
a = 4.0
x = 0.5
pr1 = gammaCdf(x, a)
print("The probability that X is less than 0.5 is %6.4f" % pr1)
x = 1.0
pr2 = gammaCdf(x, a) - pr1
print("The probability that X is between 0.5 and 1.0 is %6.4f" % pr2)
Output¶
The probability that X is less than 0.5 is 0.0018
The probability that X is between 0.5 and 1.0 is 0.0172
Informational Errors¶
IMSLS_ARG_LESS_THAN_ZERO |
Since “x” = # is less than zero, the
distribution function is zero at
“x ”. |
Fatal Errors¶
IMSLS_X_AND_A_TOO_LARGE |
Since “x ” = # and “a ” =
# are so large, the algorithm would
overflow. |