machine (integer)
Returns integer information describing the computer’s arithmetic.
Synopsis
#include <imsl.h>
long imsl_i_machine(int n)
Required Arguments
int n (Input)
Index indicating which value is to be returned. It must be between 0 and 12.
Return Value
The requested value is returned. If n is out of range, then NaN is returned.
Description
The function imsl_i_machine returns information describing the computer’s arithmetic. This can be used to make programs machine independent.
imsl_i_machine(0) = Number of bits per byte
Assume that integers are represented in M-digit, base-A form as
where σ is the sign and 0 ≤ xk < A for k = 0, …, M. Then,
n | Definition |
|---|
0 | C, bits per character |
1 | A, the base |
2 | Ms, the number of base-A digits in a short int |
3 | |
4 | Ml, the number of base-A digits in a long int |
5 | |
Assume that floating-point numbers are represented in N-digit, base B form as
where σ is the sign and 0 ≤ xk < B for k = 1, …, N for and E$ ≤ E ≤ E".
Then,
n | Definition |
|---|
6 | B, the base |
7 | Nf, the number of base-B digits in float |
8 | |
9 | |
10 | Nd, the number of base-B digits in double |
11 | |
12 | |
Example
This example prints all the values returned by imsl_i_machine on a 32-bit machine with IEEE (Institute for Electrical and Electronics Engineer) arithmetic.
#include <imsl.h>
#include <stdio.h>
int main() {
int n;
long ans;
for (n = 0; n <= 12; n++) {
ans = imsl_i_machine(n);
printf("imsl_i_machine(%d) = %ld\n", n, ans);
}
}
Output
imsl_i_machine(0) = 8
imsl_i_machine(1) = 2
imsl_i_machine(2) = 15
imsl_i_machine(3) = 32767
imsl_i_machine(4) = 31
imsl_i_machine(5) = 2147483647
imsl_i_machine(6) = 2
imsl_i_machine(7) = 24
imsl_i_machine(8) = -125
imsl_i_machine(9) = 128
imsl_i_machine(10) = 53
imsl_i_machine(11) = -1021
imsl_i_machine(12) = 1024
